Errors, bugs, questions - page 1424

[Vladimir Karputov]

Vladimir Pastushak:
So the history will start to be written from the moment the symbol is set in the market overview ?

Yes or after the history is turned in the indicator/script/advisor.

[[Deleted]]

What kind of bug is this? It doesn't happen all the time, it just pops up from time to time.

NormalizeDouble(value, 4);

but outputs this

0.5484000000001

[Vladimir Pastushak]

Itum:

What kind of bug is this? It doesn't keep popping up every once in a while.

NormalizeDouble(value, 4);

it outputs this

0.5484000000001

Where does it go ?

[Mikhail Tkachev]

Itum:

What kind of bug is this? It doesn't keep popping up every once in a while.

NormalizeDouble(value, 4);

and prints this

0.5484000000001

This is from the help:

NormalizeDouble
................................
Please note that when output to Journal using Print(), a normalized number may contain more decimal places than you expect. For example,

double a=76.671;// normalized number with 3 decimal places Print("Print(76.671)=",a);// print it as is Print("DoubleToString(a,8)=",DoubleToString(a,8));// print with a specified accuracy

will output in the terminal:

DoubleToString(a,8)=76.67100000 Print(76.671)=76.67100000000001

[[Deleted]]

Vladimir Pastushak:
Where does it output ?

write to a file.

[Yury Kirillov]

Mike:

This is from the reference:

NormalizeDouble
................................
Please note that when output to Journal using Print(), a normalized number may contain a larger number of decimal places than you expect. For example,

double a=76.671;// normalized number with 3 decimal places Print("Print(76.671)=",a);// print it as is Print("DoubleToString(a,8)=",DoubleToString(a,8));// print it with the specified accuracy

will give out in the terminal:

DoubleToString(a,8)=76.67100000 Print(76.671)=76.67100000000001

What's the bug?

[[Deleted]]

Yury Kirillov:

What's the bug?

is that it has to be 4 digits ! There are cases that give 4 characters, and there are cases with ... 0000000001 ! Why is it that the same function sees different values ?

How do I round the value to 4 digits ...

-----------------------------------------------------------------------------------

NormalizeDouble(value, 4);

but outputs this

0.5484000000001

[Vladimir Karputov]

Itum:

is that it has to be 4 digits ! There are cases that give 4 characters, and there are cases with ... 0000000001 ! Why is it that the same function sees different values ?

How do I round the value to 4 digits ...

-----------------------------------------------------------------------------------

NormalizeDouble(value, 4);

but outputs this

0.5484000000001

DoubleToString

[[Deleted]]

Why can't I do this?

 for(int h=0; h<=10;h++){
      for(int d=10; d<=20;d++){

      min_array[h]=d;

} }

How to implement such a code ?

[Vladimir Karputov]

Itum:

Why can't you do that?

How to implement this code ?

Use a code styler.

And an array must first be declared before it can be accessed:

   int min_array[10];
   for(int h=0; h<=10;h++)
     {
      for(int d=10; d<=20;d++)
        {
         min_array[h]=d;
        }
     }