[WARNING CLOSED!] Any newbie question, so as not to clutter up the forum. Professionals, don't go by. Can't go anywhere without you. - page 1053
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Hi-Lo 5 minutes is correct, but 10 minutes just doesn't exist so I thought low and high everywhere.
about 144 10 minutes - you still have to count 10 minutes starting at --:-5. and not just 10 minutes.
and then go on with your reasoning...
You have two blocks - in the first you calculate your minimax - in the second you enter data into arrays...
Write down the steps... - with your hands...
main loop - start()
you get the date time (five minutes) OHLC
и...
1 block
2 block
end strart
should I make an array for each range period within a day? that's hundreds, over a thousand arrays)
Just 5 minutes alone is 120, 10 minutes less by 1, 15 minutes less by 2, etc.
I will do it, if there are no other options
on the other hand... why are you only fixated on 5 minutes.... Why don't you count the days of the week?
you don't need to go to the doctor - in a year, at 4:30-17:50 on Fridays, the market will be more volatile than on other days
It's from an old book, and I'm not interested in an hourly rate, but from 5 minutes to 2 hours.
So is it possible to write the data to a file and then do calculations with it? I think hundreds of arrays is a worse option.
Listen... press F2 and you'll see a five-minute archive... so build what you need from them.... - first you say you need data, then you wonder if there will be 1000 variants and now you want to repeat the archive?
---
you first say you want the data, then you are surprised that there will be 1000 variations and now you want to repeat the archive?
what's this nonsense, i don't get it)
so you're making one yourself -
eddy 17.12.2010 01:25
should i make an array for each range period within a day? it's hundreds, more than a thousand arrays)
first, do it for just 5 minutes (288 elements in the 1st array) - and see the result...
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