Errors, bugs, questions - page 2336

[Nikolai Semko]

By the way, I've noticed that the profiler has stopped working on large programmes. :((

[Alain Verleyen]

Nikolai Semko :
By the way, I noticed that the profiler has stopped working on big programs. :((

What are big programmes?

I use it without any problems on Build 1953.

[Nikolai Semko]

Alain Verleyen:

What are big programmes?

I use it without any problems on Build 1953.

Yes, my apologies. I made the wrong conclusion.
I had a 1950 build and profiling didn't work on all indicators.
Upgraded to 1954 build. Now the profiling is working.

[fxsaber]

There are all sorts of nuances with static variables. What is the reason for this behaviour on both platforms?

#property strict

int f()
{
  static const string Symb = _Symbol;
  
  Print(Symb);
  
  return(0);
}

const int Init = f(); // Пусто

void OnStart()
{
  f(); // Не пусто
}

[Vladimir Pastushak]

Website history has not been updated since 30 November ...

[fxsaber]

Forum on trading, automated trading systems and trading strategy testing

Bugs, bugs, questions

fxsaber, 2018.11.09 15:34

In the Tester whose event is generated first, the tick or the timer?

For example, Timer should be called at 12:00:00.000. And there is a tick with the same time. Which is triggered first, OnTimer or OnTick?

Forum on trading, automated trading systems and strategy testing

Bugs, bugs, questions

Slava, 2018.11.09 16:18

Timer first

Unfortunately, this is not always the case. If a pending level triggered on a tick, OnTick is called first and only then OnTimer.

@Slava, do you think this situation is correct?

[A100]

fxsaber:

There are all sorts of nuances with static variables. What is the reason for this behaviour on both platforms?

Because this is not C++. There is a special logic here: Init is initialized before Symb

[fxsaber]

A100:

Because this is not C++. There is a special logic here: Init is initialized before Symb

I need to understand this logic or read it somewhere.

[A100]

fxsaber:

I would like to understand this logic or read it somewhere.

void f()
{
static a;
}
static b;

actually means

void f()
{
}
static b;
static a;

first the freestanding static, and in {} then

[fxsaber]

A100:

actually means

first of all, freestanding static, well, in {} then

Got it, thanks!