Coding help - page 342

[Mladen Rakic]

freakout:
http://www.forexmt4.com/mt_yahoo/Pattern_Hammer_Shooting_Star.mq4 - but in this one it's possible... I know that there is a way to fix it, because it works in a similar indicators, but here something is wrong with the code...

From what I see, that one too is showing the patterns with at least 1 bar delay. The more you go to more complicated paters (which that indicator is not able to recognize at all) the bigger the odds are that the delay will have to be bigger too

[Dawid Ciechowski]

mladen:
From what I see, that one too is showing the patterns with at least 1 bar delay. The more you go to more complicated paters (which that indicator is not able to recognize at all) the bigger the odds are that the delay will have to be bigger too

no, it appears immediately after candle close if shift value is equal to 1 when shift=2 then you have a 1 bar delay I've checked it multiple times and the only problem in my indicator is that when I change shift=2 to shift=1 it moves everything by 1 candle to the right - not to the left, so something is wrong...

[Mladen Rakic]

freakout:
no, it appears immediately after candle close if shift value is equal to 1 when shift=2 then you have a 1 bar delay I've checked it multiple times and the only problem in my indicator is that when I change shift=2 to shift=1 it moves everything by 1 candle to the right - not to the left, so something is wrong...

I don't know what indicator are you talking about now

If you are talking about the one from the link, if you take a look at this part of the code :

shift1 = shift + 1;

shift2 = shift + 2;

shift3 = shift + 3;

shift4 = shift + 4;

You will see that (due to that "+1" part in the first line) it always lags at least 1 bar. Try changing the 1,2,3,and 4 to 0,1,2 and 3 (who knows, might work). If you find similar part of code in the other try to do the same thing with it too

[Triip]

I found a nice Murrey Math indicator but those lines over the screen is little bit disturbing and I would like to cut those horizontal lines with RAY. I tried to add "ObjectSet(buff_str, OBJPROP_RAY, false);" but it didn't work out.

So maybe someone can help me out?

[emmany4]

Hello Mladen, thanks for all your help in this forum. Pls can U help to make this indicator to work with the EA, to buy, sell and close positions when the arrow shows up. I intend to use the indicator settings in MTF mode in a particular time frame which has proved not to repaint.

Thanks in advance.

[Gway]

Mladen, I don't know how to resolve this situation.

Help me please if you have time.

Thanks!

For example:

When Buffer = 3, Buffer = 2, Buffer = 1, Buffer = 1, Buffer = 1, Buffer = 1; "max" data is correct.

---------------------------------------------------------------------------------------

int Lines_Break = 3;

int j = i; while (Buffer [j + 1] == Buffer [j + 2]) j ++;

double max = Buffer [ArrayMaximum (Buffer, Lines_Break, j + 1)];

---------------------------------------------------------------------------------------

However, this time when the array becomes: Buffer = 3, Buffer = 2, Buffer = 2, Buffer = 2, Buffer = 2, Buffer = 1; "max" data is wrong.

[Mladen Rakic]

Anyway:
Mladen, I don't know how to resolve this situation.

Help me please if you have time.

Thanks!

For example:

When Buffer = 3, Buffer = 2, Buffer = 1, Buffer = 1, Buffer = 1, Buffer = 1; "max" data is correct.

---------------------------------------------------------------------------------------

int Lines_Break = 3;

int j = i; while (Buffer [j + 1] == Buffer [j + 2]) j ++;

double max = Buffer [ArrayMaximum (Buffer, Lines_Break, j + 1)];

---------------------------------------------------------------------------------------

However, this time when the array becomes: Buffer = 3, Buffer = 2, Buffer = 2, Buffer = 2, Buffer = 2, Buffer = 1; "max" data is wrong.

You are testing only 3 elements (Lines_break elements) and your start position (j+1 expression) should be i - no need to alter it. I am assuming that n this case you are working with buffer, not an array)

[Gway]

mladen:
You are testing only 3 elements (Lines_break elements) and your start position (j+1 expression) should be i - no need to alter it. I am assuming that n this case you are working with buffer, not an array)

How do I put equal Buffer into a unit?

For example: "Buffer = Buffer = Buffer = Buffer "

[Mladen Rakic]

Anyway:
How do I put equal Buffer into a unit? For example: "Buffer = Buffer = Buffer = Buffer "

Anyway

As I see from your code you do not need that. You are looking for a maximal value. If there is n maximal values or just one, it does not matter. The important is that the maximal value is identified

[Gway]

mladen:
Anyway As I see from your code you do not need that. You are looking for a maximal value. If there is n maximal values or just one, it does not matter. The important is that the maximal value is identified

Well, I'll try another approach.

Thanks