An optimization list based on inputs needed

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Very detailed and strong programmer I would be glad to see again
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Great Customer :)

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I need a way to get all input parameter combinations, to make optimizations. Examples:

input int InpKPeriod=5; // K Period
input int InpDPeriod=3; // D Period
input int InpSlowing=3; // Slowing
5*3*3=45 different combinations
input int InpDepth=12;     // Depth
input int InpDeviation=5;  // Deviation
input int InpBackstep=3;   // Backstep
12*5*3=180 different combinations
extern int    MaPeriod      = 20;
extern int    MaMethod      = MODE_SMA; //4 methods
extern int    PriceToUse    = 1; //6 prices
extern int    AtrPeriod     = 50;
extern double AtrMultiplier = 2.5;
extern int    MaAtrShift    = 1;
extern string MaMethods     = "";
extern string _0            = "0 - SMA";
extern string _1            = "1 - EMA";
extern string _2            = "2 - SMMA";
extern string _3            = "3 - LWMA";
20*4*6*50*25(2.5)*1*3=1,800,000 combinations
extern    int MaMetod      =2;
extern    int MaPeriod     =6;
extern    int MaMetod2     =3;
extern    int MaPeriod2    =2;
2*6*3*2=72 combinations
extern int FastMA_Mode = 3; //4 methods
extern int FastMA_Period =   3; //6 prices
extern int FastPriceMode = 6;
extern int SlowMA_Mode = 3; //4 methods
extern int SlowMA_Period =   34;
extern int SlowPriceMode = 6; //6 prices
4*6*6*4*34*6= 117,504 combinations
This code must be easily adaptable, maybe portable, for various inputs.
for(int iCnt=0; iCnt=(Total Combinations); iCnt++){
 
//each settings combination will be used here..
 Example
 iCnt==0 so InpKPeriod=5, InpDPeriod=3, and InpSlowing=3
 iCnt==1 so InpKPeriod=4, InpDPeriod=3, and InpSlowing=3
 iCnt==2 so InpKPeriod=3, InpDPeriod=3, and InpSlowing=3
 iCnt==3 so InpKPeriod=2, InpDPeriod=3, and InpSlowing=3
 iCnt==4 so InpKPeriod=1, InpDPeriod=3, and InpSlowing=3
}

Result: All combinations of a selection of inputs, as array variables, based on a array index beginning with 0 that can be utilized in a for loop.

Please apply if you can easily do this job.





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