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Very detailed and strong programmer I would be glad to see again
開発者からのフィードバック
Great Customer :)
指定
I need a way to get all input parameter combinations, to make optimizations. Examples:
input int InpKPeriod=5; // K Period input int InpDPeriod=3; // D Period input int InpSlowing=3; // Slowing 5*3*3=45 different combinations
input int InpDepth=12; // Depth input int InpDeviation=5; // Deviation input int InpBackstep=3; // Backstep 12*5*3=180 different combinations
extern int MaPeriod = 20; extern int MaMethod = MODE_SMA; //4 methods extern int PriceToUse = 1; //6 prices extern int AtrPeriod = 50; extern double AtrMultiplier = 2.5; extern int MaAtrShift = 1; extern string MaMethods = ""; extern string _0 = "0 - SMA"; extern string _1 = "1 - EMA"; extern string _2 = "2 - SMMA"; extern string _3 = "3 - LWMA"; 20*4*6*50*25(2.5)*1*3=1,800,000 combinations
extern int MaMetod =2; extern int MaPeriod =6; extern int MaMetod2 =3; extern int MaPeriod2 =2; 2*6*3*2=72 combinations
extern int FastMA_Mode = 3; //4 methods extern int FastMA_Period = 3; //6 prices extern int FastPriceMode = 6; extern int SlowMA_Mode = 3; //4 methods extern int SlowMA_Period = 34; extern int SlowPriceMode = 6; //6 prices 4*6*6*4*34*6= 117,504 combinationsThis code must be easily adaptable, maybe portable, for various inputs.
for(int iCnt=0; iCnt=(Total Combinations); iCnt++){ //each settings combination will be used here.. Example iCnt==0 so InpKPeriod=5, InpDPeriod=3, and InpSlowing=3 iCnt==1 so InpKPeriod=4, InpDPeriod=3, and InpSlowing=3 iCnt==2 so InpKPeriod=3, InpDPeriod=3, and InpSlowing=3 iCnt==3 so InpKPeriod=2, InpDPeriod=3, and InpSlowing=3 iCnt==4 so InpKPeriod=1, InpDPeriod=3, and InpSlowing=3 }
Result: All combinations of a selection of inputs, as array variables, based on a array index beginning with 0 that can be utilized in a for loop.
Please apply if you can easily do this job.
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