Операция инкремента и декремента применяются только к переменным, к константам не применяются. Префиксныe инкремент (++i) и декремент (--k) применяются к переменной непосредственно перед использованием этой переменной в выражении. Могут возникнуть вычислительные проблемы при переносе вышеуказанного выражения из одной среды программирования в...
Thank you, but I have a question. My buffers are indicative and have a view.
Will it work in this form?
The buffer is a regular array. I think you are writing longer questions than you could check with a simple example. Everything you wrote will work and can even be simplified.
Please tell me. There are two buffers with values in the indicator.
Trying to get the value of the third buffer.
Nothing.
What am I doing wrong?
Thank you.
Please tell me. There are two buffers with values in the indicator.
Trying to get the value of the third buffer.
Nothing.
What am I doing wrong?
Thank you.
You do not receive. You are writing it down.
You do not receive. You are writing it down.
You assign a value to the 3rd buffer. "And nothing" is what? )))
How are you trying to get this value?
You assign a value to the 3rd buffer. "And nothing" is what? )))
How are you trying to get this value?
I'm assigning a quotient from dividing the values of the second and first buffers.
An empty buffer is obtained.
I assign the quotient from dividing the values of the second and first buffers.
The buffer is empty.
Maybe it's not the buffer that is empty, but the graph?)
I assign the quotient from dividing the values of the second and first buffers.
An empty buffer is obtained.
That's how it works.
That's how it works.
Thank you, but I have a question. The buffers I have are indicative and look like.
Will it work in this form?
Thank you, but I have a question. My buffers are indicative and have a view.
Will it work in this form?
The buffer is a regular array. I think you are writing longer questions than you could check with a simple example. Everything you wrote will work and can even be simplified.