Mega-brains don't communicate. Is it possible to say that they can choose their probability of sending a message under the terms of the problem? That would mean that they got together and decided "we will send a message with a probability of 0.75".
(4) For Mega Brain Day, N name T-shirts were issued, strictly one per person. The megabrains were supposed to enter the room one by one in a certain order, find their T-shirt, put it on and leave. But unfortunately, the first megabrain dropped out of action and was replaced by a mini-brain, who didn't have time to get his own T-shirt. The procedure remains the same, but the mini-brain enters the room first and puts on any T-shirt it finds. Next, each megabrain, if it does not find its own T-shirt, puts on any other of the remaining ones. What is the probability that the last person to enter the room puts on his T-shirt?
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The probability of winning is very high compared to what it seems at first.
This would already mean that they got together and decided "we'll send the message with a 0.75 probability".
No, it would mean that they have understood and found the optimality.
I see, then my answer is: send a letter with a probability of 0.1. If MM came to this conclusion, the probability of getting a win is 0.5.
There is a clear rationale )
I see, then my answer is: send a letter with a probability of 0.1. If MM has come to this conclusion, the probability of winning is 0.5.
There is a clear rationale )
0.5 won't work. There's 0.39 roughly (0.3874). Something you did wrong with the formula.
C(10,1)*x*(1-x)^9.
Is the proof (conclusion) needed? Because that's exactly the point, if I've counted it correctly.
Do you need a proof (conclusion)? Because that's exactly the point, if I've counted it correctly.
Conclusion - in a private message, if you want. Or a brief substantiation.
Otherwise a numerical answer will suffice. My answer is surprisingly simple. I don't know if it's right or wrong yet.
I'd love to see the conclusion if it's simpler than mine. I have five lines of formulas and the same number of explanations.