Exclude/remove a specific element of an Array with string data
Move higher elements down to the deleted one by one and resize the array.
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Hello,
I would like to code a simple situation in theory, but i am kind of struggling with that. Imagine I have an array with string data like this:
FirstArray [8] = {"A","B","C","D","E","F","G","H"}
I am having the need to remove one specific position which can be any of the 8 elements, and then resize the array to 7 elements. For instance, let´s say I want to remove index 3, which represents string "C" of the array above. Succeeding on this would mean I end up having my final array like this:
FinalArray [7] = {"A","B","D","E","F","G","H"}
Can you help me on this?
Thanks you a lot in advance.
Hello.
There are 2 approaches .
In the first one ,you dont care about the order of the array elements ,so you pull the last element ,place it in the position of the element you want to delete ,and reduce the array.(overwrite)
First Method :
void FirstMethod(string &reference_to_array[],int element_to_remove) { //get current size int current_size=ArraySize(reference_to_array); //if size okay and element okay if(current_size>0&&element_to_remove<=current_size&&element_to_remove>0) { //overwrite reference_to_array[element_to_remove-1]=reference_to_array[current_size-1]; //shrink if(current_size-1==0){ArrayFree(reference_to_array);} if(current_size-1>0){ArrayResize(reference_to_array,current_size-1,0);} } //if size okay and element okay ends here }
to use this call :
FirstMethod(FirstArray,3);//we pass the reference to the array ,and the element to be removed (the element in the array will actually be -1 ,so [2] will be removed
In the second approach , you care about the order of the elements so you pull everything below the removed element up
Second Method :
void SecondMethod(string &reference_to_array[],int element_to_remove) { //get current size int current_size=ArraySize(reference_to_array); //if size okay and element okay if(current_size>0&&element_to_remove<=current_size&&element_to_remove>0) { //loop from element to remove -1 which is the location in the array to total elements -2 because the last actual element has nothing to pull for(int p=(element_to_remove-1);p<=(current_size-2);p++) { reference_to_array[p]=reference_to_array[p+1];//pull up the element below } //shrink if(current_size-1==0){ArrayFree(reference_to_array);} if(current_size-1>0){ArrayResize(reference_to_array,current_size-1,0);} } //if size okay and element okay ends here }
to use this call :
SecondMethod(FirstArray,3);
Hello.
There are 2 approaches .
In the first one ,you dont care about the order of the array elements ,so you pull the last element ,place it in the position of the element you want to delete ,and reduce the array.(overwrite)
First Method :
to use this call :
In the second approach , you care about the order of the elements so you pull everything below the removed element up
Second Method :
to use this call :
There is no need for any of the above.
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Hello,
I would like to code a simple situation in theory, but i am kind of struggling with that. Imagine I have an array with string data like this:
FirstArray [8] = {"A","B","C","D","E","F","G","H"}
I am having the need to remove one specific position which can be any of the 8 elements, and then resize the array to 7 elements. For instance, let´s say I want to remove index 3, which represents string "C" of the array above. Succeeding on this would mean I end up having my final array like this:
FinalArray [7] = {"A","B","D","E","F","G","H"}
Can you help me on this?
Thanks you a lot in advance.