Any rookie question, so as not to clutter up the forum. Professionals, don't pass by. Nowhere without you - 6. - page 1134

[Nauris Zukas]

Hello. If you don't know beforehand how many elements will be in the array, how do you declare the array so that the array increases with each new element?

An example to make it clearer:

double HighA[]; // ??????????????????

for(int i=0; i<1000; i++)
{
if(A[i]<B[i])
HighA[i]=A[i];
}
Print(">>>>>>>>>>>..ArraySize(HighA)= ",ArraySize(HighA));

[Alexey Viktorov]

Nauris Zukas:

Hello. If you don't know beforehand how many elements will be in the array, how do you declare the array so that the array increases with each new element?

An example to make it clearer:

double HighA[]; // ??????????????????

for(int i=0; i<1000; i++)
{
if(A[i]<B[i])
HighA[i]=A[i];
}
Print(">>>>>>>>>>>..ArraySize(HighA)= ",ArraySize(HighA));

You should read the documentation more often.

[Nauris Zukas]

Alexey Viktorov:
You should read the documentation more often.

I've read and tried but I get an "array out of range" error. In the example it looked like this:

      double HighA[];
      for(int i=0; i<1000; i++)
        {
         if(A[i]<B[i])
           {
            countHlines++;
            ArrayResize(HighA,countHlines);
            HighA[i]=A[i];
           }
        }
      Print(">>>>>>>>>>>..ArraySize(HighA)= ",ArraySize(HighA));

[Alexey Viktorov]

Nauris Zukas:

I've read and tried but I get an "array out of range" error. On the example it looked like this:

      double HighA[];
      for(int i=0; i<1000; i++)
        {
         if(A[i]<B[i])
           {
            countHlines++;
            ArrayResize(HighA,countHlines);
            HighA[i]=A[i];
           }
        }
      Print(">>>>>>>>>>>..ArraySize(HighA)= ",ArraySize(HighA));

When condition A[i] < B[i] is not fulfilled, the array size remains unchanged and the loop counter is incremented. That's why it is out of range.

Try it this way.

      double HighA[];
      for(int i=0; i<1000; i++)
        {
         if(A[i]<B[i])
           {
            int size = ArraySize(HighA);
            ArrayResize(HighA, size+1);
            HighA[size]=A[i];
           }
        }
      Print(">>>>>>>>>>>..ArraySize(HighA)= ",ArraySize(HighA));

[Nauris Zukas]

Alexey Viktorov:

When the A[i] < B[i] condition is not satisfied, the array size remains unchanged and the loop counter is incremented. That's why it is out of bounds.

Try it this way.

      double HighA[];
      for(int i=0; i<1000; i++)
        {
         if(A[i]<B[i])
           {
            int size = ArraySize(HighA);
            ArrayResize(HighA, size+1);
            HighA[size]=A[i];
           }
        }
      Print(">>>>>>>>>>>..ArraySize(HighA)= ",ArraySize(HighA));

Thank you! It all works now !

[Vitaly Muzichenko]

Nauris Zukas:

I've read and tried but I get an "array out of range" error. In the example it looked like this:

      double HighA[];
      for(int i=0; i<1000; i++)
        {
         if(A[i]<B[i])
           {
            countHlines++;
            ArrayResize(HighA,countHlines);
            HighA[i]=A[i];
           }
        }
      Print(">>>>>>>>>>>..ArraySize(HighA)= ",ArraySize(HighA));

Well that would work faster

  int countHlines=0;
  double HighA[];
      for(int i=0; i<1000; i++)
        {
         if(A[i]<B[i])
           {
            countHlines++;
            ArrayResize(HighA,countHlines);
            HighA[countHlines-1]=A[i];
           }
        }
      Print(">>>>>>>>>>>..ArraySize(HighA)= ",ArraySize(HighA));


// Вариант №2
  int countHlines=-1;
  double HighA[];
      for(int i=0; i<1000; i++)
        {
         if(A[i]<B[i])
           {
            countHlines++;
            ArrayResize(HighA,countHlines+1);
            HighA[countHlines]=A[i];
           }
        }
      Print(">>>>>>>>>>>..ArraySize(HighA)= ",ArraySize(HighA));

[Nauris Zukas]

Vitaly Muzichenko:

Well, it will work faster that way

  int countHlines=0;
  double HighA[];
      for(int i=0; i<1000; i++)
        {
         if(A[i]<B[i])
           {
            countHlines++;
            ArrayResize(HighA,countHlines);
            HighA[countHlines-1]=A[i];
           }
        }
      Print(">>>>>>>>>>>..ArraySize(HighA)= ",ArraySize(HighA));


// Вариант №2
  int countHlines=-1;
  double HighA[];
      for(int i=0; i<1000; i++)
        {
         if(A[i]<B[i])
           {
            countHlines++;
            ArrayResize(HighA,countHlines+1);
            HighA[countHlines]=A[i];
           }
        }
      Print(">>>>>>>>>>>..ArraySize(HighA)= ",ArraySize(HighA));

Thank you, I see! It will be faster because of the ArraySize, does it somehow slow it down?

[Alexey Viktorov]

Nauris Zukas:
Thank you, I see! It will be faster because of ArraySize, does it slow it down somehow?

Not much, but it's clear and error-proof.

[Nauris Zukas]

Alexey Viktorov:
Not much, but it's clear and error-proof.

Thank you!

[lomogun]

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