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About the ants:
A=3+6-9
B=8+4-12
C=10+1-11
D=5+2-7
Bingo! :)))
alsu, зачод! Да, это и был вопрос а):
Какой остаток может давать квадрат целого числа при делении на 8?
in hexadecimal also solves the problem:)))
про муравьев:
A=3+6-9
B=8+4-12
C=10+1-11
D=5+2-7
Бинго! :)))
drawпро муравьев:
A=3+6-9
B=8+4-12
C=10+1-11
D=5+2-7
Бинго! :)))
yes yes draw it
да да нарисуй
I'll give it a try.
I'm getting confused again.
As if they don't split into two groups at the output of edge 12, there are not many more options, and when one of the groups splits ( or joins) at the next vertex even less
I may have missed something ...
There hasn't been any attempt of analysis, in fact, yet (mine doesn't count yet, because I know what we will come to - two vertices connected by 6 edges - but I don't know how to restore the original cube from this construction). So far we believe Sank, hoping that the solution exists.
Да пока ни одной попытки анализа, собственно, и не было (моя не считается пока, т.к. я знаю, к чему придем, - к двум вершинам, соединенным 6 ребрами, - но не знаю, как из этой конструкции восстановить исходный куб). Пока верим только Саньку, надеясь на то, что решение существует.
Maybe they're not climbing on the ribs, but on the edges?
Only Sanyok can tell you that. I couldn't find such a task in the search engine.