[Archive!] Pure mathematics, physics, chemistry, etc.: brain-training problems not related to trade in any way - page 628

 
Roman.:
Mata - no. CrH3.

He is referring to such a position. (The amendment he sent, it was apparently wiped out wholesale).

But this position is impossible to get in 4 moves, if played by the rules.

[Deleted]  

Briefly

D7-D5

E7-E5

G7-G6

D8-G5.

If I understand correctly D8 is the queen, right?

 
Kocty2:

Briefly

D7-D5

E7-E5

G7-G6

D8-G5.

If I understand correctly D8 is the queen, right?

Longer: On the fourth move White cannot go Krg3-h4, because the square h4 is under the battle of Black's queen. According to the rules of chess, it is forbidden to move the king under check.
 

The thread has become very slow when adding posts.


Open part two https://www.mql5.com/ru/forum/140533

 
MetaDriver:

He is referring to such a position. (He sent the amendment, it was apparently wiped out wholesale).

But this position is impossible to get in 4 moves, if you play by the rules.

Thank you. That's me - got it.
 
Roman.:
Thank you. That's me - got it.
OK.
 
Continue the topic here.
 
Yurixx #:

By the way, a cube is a tetrahedron with a triangular pyramid on each face. And a triangular pyramid differs from a tetrahedron only in proportions of the sides, but precisely also has 4 sides and 6 edges. Thus both a tetrahedron and a triangular pyramid are murahedrons.

If we put a cube together from a tetrahedron and 4 pyramids, the edges of the tetrahedron will be diagonals of the faces of the cube. And along these diagonals 1 edge of the tetrahedron and 2 edges of the adjacent pyramids coincide. A new problem arises.

Take 1 natural murahedron and 1 murahedron with doubled numbers along the edges. From these two objects, using as many as is necessary, fold the cube so that the ants do not walk along the diagonals. That is, the total number of ants on the edges of the tetrahedron and coinciding edges of the pyramids should be equal to zero. At that, of course, it is desirable to keep the former condition - all numbers on the edges of the cube are different.

I'm not sure that the formulation of the problem is correct - I made it up myself. :-)

But if it's correct or can be made correct, then its solution is also a solution of Sanyooook's problem.

dude, wtf? 😂

principles of science work everywhere, taking abstract things doing abstract stuff in other area of competence its foolish 😅