When dividing the tea into 2 parts (and not separating the coffee), I get tea-55 and coffee-45. Here I am wondering how much more you can increase the final temperature difference.
First ten divisions:
0
95.000000
5.000000
5.000000
95.000000
1
50.000000
50.000000
50.000000
50.000000
2
38.750000
61.250000
55.000000
45.000000
3
33.125000
66.875000
57.031250
42.968750
4
29.609375
70.390625
58.136000
41.864000
5
27.148438
72.851563
58.831019
41.168981
6
25.302734
74.697266
59.308749
40.691251
7
23.852539
76.147461
59.657369
40.342631
8
22.674255
77.325745
59.923009
40.076991
9
21.692352
78.307648
60.132156
39.867844
10
20.857735
79.142265
60.301104
39.698896
the two left columns are for both drinks split, the two right columns are for one drink split.
--
the rest (up to 1000) in the trailer // I'd be interested in exact limits, but that's up to you, I'll pass. :)
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I'd rather have 95 and 5.
When dividing the tea into 2 parts (and not separating the coffee), I get tea-55 and coffee-45. Here I am wondering how much more you can increase the final temperature difference.
First ten divisions:
the two left columns are for both drinks split, the two right columns are for one drink split.
--
the rest (up to 1000) in the trailer // I'd be interested in exact limits, but that's up to you, I'll pass. :)
the rest (up to 1000) in the trailer // I'd be interested in exact limits, but that's up to you, I'll pass. :)
Well, not bad.
I'm not gonna do the math. Too many parameters. You can divide it into unequal parts.
I'll look for something similar on braingames.ru.
Not bad.
I'm not going to calculate it. Too many parameters. You can divide it into unequal parts.
Coward. You only need a limit (maximum) of the difference (at N -> ∞).
FAQ: Dividing into unequal parts always results in less difference than dividing into equal parts (easy to check).
Coward. We only need to calculate the limit (maximum) of the difference (at N -> ∞).
FAQ: When dividing into unequal parts, the difference is always less than when dividing into equal parts (easy to check).
Let's agree on the procedure: we divide the tea into N parts, we drop them into a litre of coffee in succession and reach thermodynamic equilibrium.
At the very end we pour all N heated parts of tea into a single container.
Right?
About the FAQ: I'm not sure, but it seems to be true.
Probably some exponent will come out in the theoretical calculation.
Mathemat:
I'll look for something like that on braingames.ru.
Let's agree on a procedure: divide the tea into N parts, lower them into a litre of coffee in succession and reach thermodynamic equilibrium.
At the very end we pour all N heated parts of tea into a single container.
Right?
I'm paraphrasing:
1. We divide the tea into N parts,
2. We lower them into a litre of coffee, reach thermodynamic equilibrium and pour the dose into a single vessel (where we refill the remaining doses).
3. measuring.
About the FAQ: not sure, but it sounds about right.
I swear by tailgates.
No way. The exponent's not bounded from above. This shit is bounded.
maximum mech speed 486 m/s
... After that, knock on the boat or..., in short, the sound of the command can't catch up with it.
maximum mech speed 486 m/s
... After that, knock on the boat or..., in short, the sound of the command can't catch up with it.
...but it can catch up with the previous claps again. ;)