Pure maths, physics, chemistry, etc.: brain-training tasks that have nothing to do with trade [Part 2] - page 35
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That's to the bank for a loan officer
Proportion then. ))))))))))))) 30/20 = X/24 ==> X=(30/20)*24=36;
Proportion then. ))))))))))))) 30/20 = X/24 => X=(30/20)*24=36;
yes yes I did.)
A cloud is not a spoon.
A raccoon doesn't wash.
The book does not read.
And if the book reads, why does the raccoon erase and the cloud spoon.
I don't know the answer.
A cloud is not a spoon.
A raccoon doesn't wash.
The book does not read.
And if the book reads, why does the raccoon erase and the cloud spoon.
I don't know the answer.
IMHO, this seems to be an abstract logic problem. The problem itself should sound something like this:
Unless: 1. The cloud is not a spoon. 2. The raccoon does not erase. 3. The book doesn't read.
Does it follow from the fact that the book reads that the raccoon is erasing and the cloud is spooning.
The answer is NO because the problem does not establish a feedback between spoons and clouds. That is, it does not follow from the fact that all clouds are spoons that all spoons are clouds. And the connections are not established: 1.direct between readers and raccoons.
2 the inverse between erasers and raccoons.
It's roughly like a problem like this - I'll simplify it on purpose:
1. Man has two arms and two legs !
2. Man can read!
The monkey has two arms and two legs. Does it follow that a monkey can read?
In this case, the familiar terms: cloud, raccoon, book, spoon - to confuse. It goes something like this.
A cloud is not a spoon.
A raccoon doesn't wash.
The book does not read.
And if the book reads, why does the raccoon erase and the cloud spoon.
I don't know the answer.
Man is a two-legged man, devoid of feathers.
So the plucked bird is also human
Please, those who have studied cryptography in depth and know what it is all about, do not answer this problem. Allow the rest of us to pick our brains.
Three paranoiacs, Andrei, Boris and Vasili, are having lunch in a restaurant. At some point the waiter comes up to them and informs them that a certain subject has approached the maître d'hôtel and has offered to pay their bill in full. The paranoiacs get paranoid: either one of the three of them has decided to show gallantry to the others in this way, or the KGB is watching them and lets them know that they are not alone.)
On the one hand, the guys respect each other's right to anonymity of payment in case it is really one of them. On the other, everyone wonders if the KGB, who may have paid for lunch, is watching them.
Suggest a procedure that would allow Andrei, Boris and Vasa to determine that the payer is one of the three of them and not the KGB, or to establish otherwise, while at the same time not in any way revealing the identity of the person who paid (in case it really was one of the three comrades).
A little hint: each of the friends has a coin that can be flipped with a random result.