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Equals. How do you mathematically get this
as suggested in the beginning.
Only take the time difference not in minutes, but in the difference in indices between bars.
as suggested in the beginning.
Only take the difference in time, not in minutes, but in the difference in indices between bars.
It will still work out in parrot-oils. Try calculating it yourself
as suggested in the beginning.
Only take the difference in time, not in minutes, but in the difference in indices between bars.
Simply put in units of bars and price in units of points.
You get sqrt((15bar)^2+(50pp)^2)
Simply put, the bar is in pips and the price is also in pips.
We get sqrt((15bar)^2+(50pp)^2)
Yeah...
What should we call it? "Eliotto point", for example.
But be sure to then multiply by Period()...
;)
Yeah...
What should we call it? "Eliotto point", for example.
But be sure to then multiply by Period()...
;)
Yes, and I will also tell you in confidence that bars can be assigned non-linearity coefficients depending on the session
then you get "Eliotto-session-point" goo-goo-goo-goo
Yeah, and I'll tell you in confidence that bars can be assigned non-linearity coefficients depending on the session
then you get "Eliotto-session-point" heh-heh-heh-heh
Multiplication by Period() is very wise :) solution.
Three screens can be screwed on...
;)
ZS: mona more
--- and if multiplying/splitting by volum only improves momentum.
And by the number of minutes in a bar maybe you should multiply at once...?
Looks like it's time to erase the cleverness, because people are scattered :o)
I still think so, and I'm not erasing anything!
The Eliotto-Point-Minutes can be quite good at building up TCs.
;)
Looks like it's time to erase the cleverness, people are scattered :o)
People ran to learn :)
Code.
:)