[Archive!] Pure mathematics, physics, chemistry, etc.: brain-training problems not related to trade in any way - page 601

 
Aleksander:

You guys :-)



))))

 
Aleksander:
well of course - first prepared the rows - and started a wave - which spun up and down through 1 row, tucking them in for the next integration...
Well, that's the whole point of this game.
 
Mathemat:
Uh-oh, that's embarrassing.

It's not about you personally, it's just a general observation about people. Even I'm noticing it myself :)
 

3 3 3 5 3 3 5 3 3 3 3 3 5 5 3 3 3 3 3 3 3 3 5 5 3 5 3 3 3 5 5 5 5 X

what is X ? (with solution formula obligatory) several options are possible...

 

One Megamogg threw the dice 2011 times and the other Megamogg threw it 2012. What is the probability that the odd numbers of the second one rolled more times than those of the first one?

The problem is scored 3 points. No cool terver formulas are needed here. Just logic and simple richematics.

 
50/50. That is, to be precise, probability = 1/2
 
GaryKa: 50/50. That is, to be precise, probability = 1/2

Let others be tortured. If anyone else knows the answer, take your time.

Reminder: you have to prove the answer. The proof is surprisingly simple and fits these numbers perfectly.

 

my megabrain(2nd) ...in fact, all sides have 1 (one) point engraved on them... because the cube is gold :-) - it's a bit like him to throw out the odd numbers...

but... the second one has 0.0004972650422675285927399303829 more than the first one :-)

 
Aleksander: my megabrain(2nd)...in fact, all the facets have 1(one) point engraved on them... because the cube is gold :-) - he got a kick out of throwing out odd numbers...

Come on, make up your mind, you old casino man! I'm telling you, there's no need to remember Bernoulli's formulae.

so... the second one has 0.0004972650422675285927399303829 more than the first one :-)

It's an insignificant statistical outlier.

 
They roll 2011 numbers equally, then roll 2012 then there is a 50/50 chance