Off-topic MT4/mql4 questions. - page 27
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Hello, everyone. The question is this.
There are several graphs. For example:
You need to use these graphs to draw their arithmetic mean curve! Apart from the graphs, there is nothing initially. No formulas, no numerical coordinates. Nothing. Just a scale on the side. And a time axis with equal time intervals.
If there is a program that can draw the arithmetic mean curve over several (up to 10) charts? If so, please give me a link or a name.
The first thing that came to mind. Is to take some circular time scale values (X axis). I transferred their values manually to the excel table. Then you can plot the resulting curve.
In essence, the X axis will be the same for all, i.e. the time period is the same. The Y-axis will have different values at a selected (circular) point in time.
Further summarize the values of these graphs from the Y-axis for 10 years - there will be 10 graphs and already build a summary table (through this formula). Next, use this table to draw the final graph.
This is a time-consuming and rough (depending on the step of the time scale) solution, which allows estimating the character of changes of spread instrument returns for a certain period of time.
Yes, manually is time-consuming.
In the end, I (for example) want to get a graph of averaged multiyear seasonal trends in a certain area (which I can construct myself on a special website), something like this:
- Here the arithmetic mean of the 5 and 15 year lines is plotted.
Yes, manually is labour-intensive.
In the end, I (for example) want to get a so-called multi-annual seasonal trend graph at a certain site, something like this:
I understood it at once, Leonid. Besides being time-consuming by hand, it is also coarse (by the step of the time scale when transferring manually)...
We need a program or something...
So the question remains open.
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As a start, you could (optionally) find at least a scanning program to translate each line graph into coordinates. And then sum up these coordinates in Excel and draw an averaged line!
- The contract of the pigs is a 20 year average graph:
If we talk specifically about this site, all the necessary data are already contained in the code of the HTML page itself (of course, those coders wrote there :))
Open the code of the page in any editor (you can directly in your browser)
We see such lines :
<area shape="poly" coords="45,282,50,268,55,262,55,272,50,278,45,292"onmousemove="showTooltip(event, '<b>[Apr 21, 2011]</b>: -17.70')"
These respectively describe the positions and values of the tooltip for each date on the chart. I think I don't need to explain what to do next - Excel rules.
And single (non-simultaneous) graphs - I can plot here: (oil 2010 September-November)
http://www.cowsandcrops-market.com/markets/spreadchart.php?spread=CLZ10&indicator=&type=LINE&volume=&grid=1&logscale=0&density=M&period=D&size=S&indicators=
If we talk specifically about this site, all the necessary data are already contained in the code of the HTML page itself (of course, those coders wrote there :))
Open the code of the page in any editor (you can directly in your browser)
We see such lines :
<area shape="poly" coords="45,282,50,268,55,262,55,272,50,278,45,292"onmousemove="showTooltip(event, '<b>[Apr 21, 2011]</b>: -17.70')"
These respectively describe the positions and values of the tooltip for each date on the chart. I think I don't need to explain what to do next - Excel rules.
I.e. it turns out that in the "source code" of the page (e.g. CLZ10 oil Tf=D in the link above) - the graph coordinates are already there:
All that's left to do is to somehow transfer them to excel?
From the whole coordinate map we are interested only in "[Apr 21, 2011]</b>: -17.70 ", copy the map to a test document, save it, and open it in excel. in excel we cut out all unnecessary columns, leaving only dates and prices. We save it as a text document. The rest of the markup as "[", "]</b>:" will be removed with any text editor and only the date and price will remain:
Could you elaborate a bit more...,
because it's not so easy to understand for inexperienced (like me) comrades... :-)
How do you get a picture like this from a picture like this?
Thank you.