How to get time in 24-hours format?

[Oleksnadr Myronchuk]

datetime dt;
/* init dt */
StringFormat("datetime = %s;", TimeToString(dt, TIME_DATE|TIME_SECONDS));

If I use the TimeToString function, I get time in 12-hours format.

The output looks like this:

datetime = 03:35:00;

First: what I do not like about this output is that I don't know whether it is am or pm now. How to know it ?

Second: For me more convenient 24-hours format. Can I convert the datetime to 24-hours string format by using standard libraries ?

[Oleksnadr Myronchuk]

I fixed it. The topic is closed

[William Roeder]

jhliguktxikdtxf: I fixed it. The topic is closed

Don't do that. Someone searching might find this thread and still be clueless. What was the problem? What solved what?

How To Ask Questions The Smart Way. 2004
     When You Ask.
          Follow up with a brief note on the solution.

[Oleksnadr Myronchuk]

I don't know "what was the problem?"... It just doesn't work right.

To fix this you need:

Get the datetime as a "long" variable and multiply it by 1000

long tc = TimeCurrent()*1000;

After that, you need to do some math... I will not explain what I do, read about "Unix time" and you will understand

https://en.wikipedia.org/wiki/Unix_time

   long millis = tc % 1000;

long second = (tc / 1000) % 60;

long minute = (tc / (1000 * 60)) % 60;

long hour = (tc / (1000 * 60 * 60)) % 24;

And all code will look like this:

   long tc = TimeCurrent()*1000;
   
   long millis = tc % 1000;
long second = (tc / 1000) % 60;
long minute = (tc / (1000 * 60)) % 60;
long hour = (tc / (1000 * 60 * 60)) % 24;
   
   Print(hour, ":", minute, ":", second,":", millis);

If someone has the same problem, and you do not understand how to solve it even after my comment, then write what exactly you do not understand. I will help you