Determining time of day

[Westie30]

I've looked into TimeCurrent() as well as CDatetime and I can't seem to figure out to determine the number of seconds elapsed in a day. I like TimeCurrent(), but I would prefer to have only the time without the date. I need to obtain the number of seconds elapsed as opposed to just the time as a string.

[Westie30]

Westie30:
I've looked into TimeCurrent() as well as CDatetime and I can't seem to figure out to determine the number of seconds elapsed in a day. I like TimeCurrent(), but I would prefer to have only the time without the date. I need to obtain the number of seconds elapsed as opposed to just the time as a string.

I just figured out to do (long)TimeCurrent(), but what exactly does this number mean? Does it include hours, minutes, and seconds? If so, how do I get seconds only?

[iRick]

I think the Time is seconds from 1900-01-01

So if you take TimeCurrent() and minus StrToTime("00:00") you'll be left with the seconds so far for the day

StrToTime will default to today's date if you don't specific one

[Soewono Effendi]

please refer to https://www.mql5.com/en/docs/constants/structures/mqldatetime

[Marco vd Heijden]

Westie30:
I just figured out to do (long)TimeCurrent(), but what exactly does this number mean? Does it include hours, minutes, and seconds? If so, how do I get seconds only?

This is seconds since Epoch, the number of seconds that have elapsed since January 1, 1970 (midnight UTC/GMT).

You can convert a datetime to a MqlDateTime:

 MqlDateTime time;

 TimeToStruct(TimeCurrent(),time);
 int Year        = time.year;        // Year
 int Month       = time.mon;         // Month
 int Day         = time.day;         // Day
 int Hour        = time.hour;        // Hour
 int Minute      = time.min;         // Minutes
 int Second      = time.sec;         // Seconds
 int Day_of_Week = time.day_of_week; // Day of week (0-Sunday, 1-Monday, ... ,6-Saturday)
 int Day_of_year = time.day_of_year; // Day number of the year (January 1st is assigned the number value of zero)

Now your seconds are an Integer.

[Westie30]

Marco vd Heijden:

This is seconds since Epoch, the number of seconds that have elapsed since January 1, 1970 (midnight UTC/GMT).

You can convert a datetime to a MqlDateTime:

Now your seconds are an Integer.

Thank you, that works great!

[William Roeder]

Westie30: I've looked into TimeCurrent() and I can't seem to figure out to determine the number of seconds elapsed in a day.

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