Get Angle in CChartObjectTrendByAngle

[Andre Lima]

Hi Guys,

Metatrader 5 

Version: 5.00 Build 1940

02 nov 2018

I Created a trend line by angle like it:

#include <ChartObjects\ChartObjectsLines.mqh>

CChartObjectTrendByAngle trend;

trend.Create(0,"HowGetAngle",0,time1, price1, time2, price2));

When I try get a angle:

double trend_angle = trend.Angle();

I get 90.0 even if I change points coordinates like it.

trend_angle.SetPoint(0,new_time1,new_price1);
trend_angle.SetPoint(2,new_time2,new_price2);

I read many times this documentation: https://www.mql5.com/en/docs/standardlibrary/chart_object_classes/obj_lines/cchartobjecttrendbyangle

Thanks

[Alain Verleyen]

MT4 but should be similar. Please check if that helps.

[Andre Lima]

Alain Verleyen:
MT4 but should be similar. Please check if that helps.

Excellent, Thanks

[Aleksandr Serbin]

Hi!

Just plug in the coordinates of two points into this function. The angle will be the same as the TrendLinebyAngle on the chart. Absolutely no bugs!

        double getAngleTwoPoints(double price1,long time1,double price2,long time2, long chart_id = 0)
          {
           double result=0;

           int x1=0,x2=0;
           int y1=0,y2=0;
           long chart = ChartGetInteger(chart_id,CHART_HEIGHT_IN_PIXELS,0);

           ChartTimePriceToXY(chart_id,0,time1,price1,x1,y1);
           ChartTimePriceToXY(chart_id,0,time2,price2,x2,y2);
           int size = (int)chart;
           y1=size-y1;
           y2=size-y2;
           double angle =NormalizeDouble((MathArctan(((double)y2-(double)y1)/((double)x2-(double)x1))*180)/M_PI,1);
           result=angle;
           return(result);
          }