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How to test a program before buying?
Eduardo Mariscal
128
Eduardo Mariscal 2015.07.26 05:27 

Hello i have been struggling with arrays, in this case i need to look to rsi in bar number 5,6 or 7 but it does a array out of rage, can you figure out what am i doing wrong,

Thanks.

Here is  the code

-------- 

double RSI[];

extern int RSIPer = 14;//RSI Period

extern int Limite_Der_a_Izq_Inicial= 0;

extern int Limite_Der_a_Izq_Final= 0; // Real time

 

int counted_bars;

int limit; 

int i;

   

int OnCalculate(const int rates_total,

                const int prev_calculated,

                const datetime &time[],

                const double &open[],

                const double &high[],

                const double &low[],

                const double &close[],

                const long &tick_volume[],

                const long &volume[],

                const int &spread[])

{

     

   counted_bars = IndicatorCounted();

   ArrayResize(RSI,Bars);

 

  

   if(counted_bars < 0) return(-1); 

   if(counted_bars > 0) counted_bars--;

   if(Limite_Der_a_Izq_Inicial != 0)

   {

     limit = Limite_Der_a_Izq_Inicial;

   }

   else

   {

     limit = Bars - counted_bars -1;

   }

   

for(i=Limite_Der_a_Izq_Final;i<limit;i++)

{

RSI[i]  = iCustom(NULL,0,"RSI",0,i);

Comment(RSI[i+2]); // it works with i and i+1, but i+2.... i+n it does not!!  

}

 return(rates_total);

      

   


Keith Watford
Moderator
7990
Keith Watford 2015.07.26 05:54  

Let's say that there are 100 bars

     limit = Bars - counted_bars -1;

 when counted_bars==0

limit=100-0-1

limit=99 

for(i=Limite_Der_a_Izq_Final;i<limit;i++)

 The maximum value of i in the loop is

limit -1

99-1 

98 is the maximum value of i

If there are 100 bars, the largest index is 99

Comment(RSI[i+2]); // it works with i and i+1, but i+2.... i+n it does not!!  

 So when the maximum value of i is reached in the loop

i=98

i+1=99

i+2=100

There is no index 100, so array out of range

whroeder1
13644
whroeder1 2015.07.26 11:47  
int counted = IndicatorCounted();
int lookback = ... // iMA(period) has look back of period.
                   // buffer[i+2] has look back of 2
                   // use maximum of all.
for(int iBar = Bars - 1 - MathMax(lookback, counted); iBar >= 0; --iBar) ...
Always count down, repainting indicators are useless.
JD4
1101
JD4 2015.07.26 16:59  
When you create an array that needs, let's say 10 spaces, you use the MyArray[10] when you create it.  But computer programs start counting array indexes at 0, so for MyArray, the correct indexes would be 0-9, which is why Gum said limit-1.  If you try using an index that is outside of that array's range, in this case, less than 0 or greater than 9, you get the error you are talking about.
Eduardo Mariscal
128
Eduardo Mariscal 2015.07.27 16:50  
JD4:
When you create an array that needs, let's say 10 spaces, you use the MyArray[10] when you create it.  But computer programs start counting array indexes at 0, so for MyArray, the correct indexes would be 0-9, which is why Gum said limit-1.  If you try using an index that is outside of that array's range, in this case, less than 0 or greater than 9, you get the error you are talking about.
Thank you very much!! 
Eduardo Mariscal
128
Eduardo Mariscal 2015.07.27 17:00  
WHRoeder:
Always count down, repainting indicators are useless.
 Now it works  !!, it was really helpful, Thanks!!!
Eduardo Mariscal
128
Eduardo Mariscal 2015.07.27 17:03  
GumRai:

Let's say that there are 100 bars

 when counted_bars==0

limit=100-0-1

limit=99 

 The maximum value of i in the loop is

limit -1

99-1 

98 is the maximum value of i

If there are 100 bars, the largest index is 99

 So when the maximum value of i is reached in the loop

i=98

i+1=99

i+2=100

There is no index 100, so array out of range. 

 

Thanks for your help !!!
JD4
1101
JD4 2015.07.27 17:14  
walomx:
Thank you very much!! 
Welcome.  It is a small point and people who are not well versed in programming often miss this small but important item.
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