# Correct brackets/bracers {} - page 2

1401
2014.09.10 11:07

Try again ..

```if(2+1>4){ Print("3"); } Print("4");   // returns 4

if(2+1>4){ Print("3"); Print("4"); }   // returns 3 and 4 OR not ?```

Make sure don't change anything in the code.

376
2014.09.10 11:38
deysmacro:

Try again ..

Make sure don't change anything in the code.

Your second example in src box.
```if(2+1>4)//3 is not bigger then 4

{ Print("3"); Print("4"); }   //No print will be done

if(2+1<4)//3 is less then 4

{ Print("3"); Print("4"); }   //Print will be done
```

I understand this but what i mean is this, witch is not equal to your first example in your src box.

``` if(2+1>4)//3 is not bigger then 4
{ Print("3"); } Print("4");   //returns 4

if(2+1<4)//3 is less then 4
{ Print("3"); } Print("4");   //returns 3 and 4```

And wrapping these, there is no difference is in result!

``` {if(2+1>4)//3 is not bigger then 4
{ Print("3"); } Print("4");}   //returns 4

{if(2+1<4)//3 is less then 4
{ Print("3"); } Print("4");}   //returns 3 and 4```

So wrapping in the whole icustom function with brackets, wont do any diffrence, unless its not a part of a complex logic.?

14750
2014.09.10 13:44
pontuso:
So wrapping in the whole icustom function with brackets, wont do any diffrence, unless its not a part of a complex logic.

## Correct brackets/bracers {}

double p0, p1, p2, p3, p4, p5;
i=0;
while(n<5)
{
if(p0>0) {p5=p4; p4=p3; p3=p2; p2=p1; p1=p0; }
p0=iCustom(Symbol(),​­ 0, ­​"mycustomindicator",­​ 0,­​ 0,­​ 3,­​ 0,­​ i);
if(p0>0) {n+=1; }
i++;
}
1. Correct
2. Be aware of the different uses of the words brackets/braces
CharacterUS EnglishUK EnglishIndia
()ParenthesesBraces, round brackets, curved brackets, oval brackets
[]BracketsSquare Brackets
{}BracesCurly bracketsflower bracket
<>Angle brackets (or chevrons)
3. What happens when you don't have five positive numbers on the chart? Simplify your logic?
double p[5];
int n=0;
for(int i=0; i < Bars && n < 5; ++i){
p[n] = iCustom(Symbol(),­​ 0,­​ "mycustomindicator",­​ 0,­​ 0,­​ 3,­​ 0,­​ i);
if(p[n]>0) ++n;
}
2584
2014.09.10 16:25

lacement of braces is uber important.

When you use any of the operators. if, while, for etc. The braces define the scope of the operator.

example

```if( var1 == var2 )

a=10;
b=20;
c=30;

// no braces is the same as braces around only the first operation so only a=10; is dependent on the if condition.

if( var1 == var2 )
{
a=10;
}
b=20;
c=30;

// b=20; c=30; are not included in the if operations and will be executed regardless in both cases.

```

```if(var1 == var2)
{
a=10;
b=20;
}
c=30;

//this time the braces mean both a=10; and b=20; will be executed when the if condition is true.
//c=30 is still outside the scope of the if operator and will be executed regardless```
14750
2014.09.10 18:45
 SDC: lacement of braces is uber important. When you use any of the operators. if, while, for etc. The braces define the scope of the operator. Except that isn't what OP is asking/doing.```function(){    code    code    {         // Useless brackets      code      code    }         // Useless brackets    code }```
2584
2014.09.10 21:21
WHRoeder:
 SDC: lacement of braces is uber important. When you use any of the operators. if, while, for etc. The braces define the scope of the operator. Except that isn't what OP is asking/doing.

Well yeah, but still, if he knows what they are supposed to be for he might better understand when they are not required.
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