Hello Geniuses
is there any way to build a link to jump to a specific chart?
my problem is that i need to open so many currencies chart to run an indicator on each one
and there is one chart that i use to take decision on which pair i will open a trade
so i need to program a link and trigger that jump to the desired pair chart.
i know it is almost impossible, but if any genius has an idea, please help me.
Thanks in advance.
- Errors, bugs, questions
- How to code?
- i need to limit number of trades in one chart
PeterMQL4:
Hello Geniuses
is there any way to build a link to jump to a specific chart?
my problem is that i need to open so many currencies chart to run an indicator on each one
and there is one chart that i use to take decision on which pair i will open a trade
so i need to program a link and trigger that jump to the desired pair chart.
i know it is almost impossible, but if any genius has an idea, please help me.
Thanks in advance.
ofcours a very simple way
look to the chart
under that chart in a horizontal line there i have listed the charts in use if i click on one of them (doubleclick if it is multichart) i get that chart
If you drag your most important to the first place in that line it is simply to find
i am talking about opening 20 charts minimum, and i could need to use any one at any time.
so organizing them is not practical .
Maximize a window, then bring the window you want to the foreground via:
Not compiled, not tested.
#include <WinUser32.mqh> #import "user32.dll" int GetAncestor(int, int); #import void ChartToForground(){ if( !IsTesting() )if( IsDllsAllowed() )if( !IsStopped() ){ int main = GetAncestor(WindowHandle( Symbol(), Period() ), 2);//GA_ROOT SetForgroundWindow(main); } } /////////////// static bool isCondition; bool wasCondition = isCondition; isCondition = ... // Price above target, isMAcrossed, etc. if(isCondition && !wasCondition) ChartToForground();Not compiled, not tested.
WHRoeder:
Maximize a window, then bring the window you want to the foreground via:
Not compiled, not tested.
Thanks a lot for your response .

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