NormalizeDouble rounding ? - page 2 12 New comment Icham Aidibe 2022.10.05 16:15 #11 Okay I let that here, it can be called like the classical normalizedouble double NormalizeNoRound(double x, int digits) { return(StringToDouble(StringSubstr(DoubleToString(x,digits+1),0,StringLen(DoubleToString(x,digits+1))-1))); } edit : double NormalizeNoRound(double x, int digits) { return(MathFloor(x*MathPow(10,digits))/MathPow(10,digits)); } 12 New comment
Okay I let that here, it can be called like the classical normalizedouble
edit :