[Archive] Learn how to make money villagers! - page 660
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I see. I'm not going to check it right now in the EA (it even has the same function by name) - just replace it (that one) with this one (yours)... I will have a closer look later...
Write in a line the approximate lots for the averaging orders for a starting date, e.g. 10,000 units of currency, i.e.: 10,000 units of currency. 10.000 currency units, i.e:
0. starting volume = 0.01 lot.
1st averaging market = 0.02 lot.
3rd averaging market = 0.03 lot.
4th = 0.05 lot.
5th = 0.09 lot
6
7
8
9
And the next averaging order should be placed after 900 seconds after the opening of the previous one, if all previous one-directional start and averaging orders were losing?
Not really, my orders are placed until there is a confirmation signal from the indicator, but not more often than every 900 seconds (I chose at random), I cannot say what will be the lot, I do not know where the market will take me, if I'm on the plus side, the lot is larger, if I'm down then smaller (no martingale for taking out losing orders), the attached report shows the lots, it is a mess
I see. Swarm go on! :-)
Asked the question in the relevant thread - see this thread. I don't know myself, it was a long time ago... :-)
Please correct, X is a constant of degree value
Corrected.
Fixed.
Well, when this equation is solved, it will be ready (probably page 666). You can run it in the tester and make a prediction of the annual interest. I have no parameters - I just want to know the result.
I have placed the indicator right in the Expert Advisor. I will change only [i-1]-->1
When we solve this equation, we will be ready. We may run it in the tester and make a forecast by annual interest. No parameters - just an interesting result
I'm trying different variants too, in particular I'm trying to determine the step of max. no-backup by dickf's script by max. history depth...
My point is that if we take the range m/o max and min over a certain period of time, wouldn't this be over-insurance... and, as a consequence, a decrease in profit as the interval of averaging orders would be increased relative to the value obtained by dividing the max failures by the max possible number of averaging orders...?
And I have checked that if we do the averaging using an arithmetic progression, we need a harder rollback to open the orders than, for example, if we double the previous order... I have such a design - see it in the tester and optimizer using different symbols:
Three types of averaging:
I'm trying different variants too, in particular the determination of step by max. no return according to dickfx's script by max. depth of history...
My point is that if we take the range m/o max and min over a certain period of time, wouldn't this be over-insurance... and, as a consequence, a decrease in profit as the interval of averaging orders would be increased relative to the value obtained by dividing the max failures by the max possible number of averaging orders...?
And I have checked that if we do the averaging using an arithmetic progression, we need a harder rollback to open the orders than, for example, if we double the previous order... I have such a design - see it in the tester and optimizer using different symbols:
Three types of averaging:
Well yes, arithmetic averaging is the fact of the guarantee of a drain. I meant about the one in whom PAMM was watched.
Also, when doubling up, it is not certain that there will be enough money. Therefore, a variant of my formula for building up the lot size - an anti-slip guarantee, according to the story
That's the design - it didn't all fit at once:
Where does 36 come from? And that's a steep coefficient. Think of the deposit - add up all the lots and multiply by the margin