[Archive!] Pure mathematics, physics, chemistry, etc.: brain-training problems not related to trade in any way - page 176

 
alsu писал(а) >>

You won't believe it, in Paint:)))

Alsu, I draw in Microsoft Office PowerPoint.

No, this thing has a lot to do with electronics, although it runs on high voltage.

 
Richie >>:



Part of the radio transmitter
 
piece of relay
 
Mischek писал(а) >>

Part of a radio transmitter

Here's a hint: this device works in 6-10 kV networks. Inside it is a semiconductor.

 
Richie >>:

Подсказываю: это устройство работает в сетях 6-10 кВ. Внутри него - полупроводник.


But it's the electrics then
 
it's clear - it's a high voltage diode
 
I've noticed that since this thread appeared, the rest of the forum has somehow dimmed:))
 

Mathemat писал(а) >>

Construct a right triangle with one vertex at the given point, one at the given line, and one at the given circle.

Conditions: You have point A, circle Y with centre in point O, line L.

Construct the geometric lines of the points through which the line must pass to be solvable:

Draw a line through point A and the circle centre O. The line intersects the circle Y at two points. Let us call them B and C.

Find intersections of circles with radius AC from points A and C with the help of compasses. We obtain two points. Let us call them D1 and D2.

Find the intersection of circles with radius AB from A and B with a compass. In this case we have 2 points. Let us call them E1 and E2.

Connect the points D1-E1 and D2-E2 by segments. Find their midpoints and make a circle with diameter D1-E1 (D2-E2 is the same size) around these midpoints.

The last two circles are the places at which the vertex of right triangle with second vertex in point A could be located

and third at the point lying on the original circle Y. Now we look at the position of the original line L with respect to these "criterion" circles.

Possible cases are:

1. The line L lies outside these circles = no solution.

2. The line L intersects one of the "vertically possible" circles = we have two solutions - at the intersection points.

3. The line L touches one of the final circles = we have 1 solution at the touching point.

4. The line L touches both final circles = there are 2 solutions - at the tangent points.

5. The line L touches one circle and intersects the other = 3 solutions - in the touch point + 2 in the intersection points.

They are constructed elementary if you have a circumscribed construction.

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// It is too boring to draw, but it seems to be clear from the careful reading.

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2 alsu: Bravissimo bisectrisemo!

 
alsu, it's not a diode, but it's close.
 

Thyristor.

Reason: