11 roosters give us 22 legs, replacing a pig with a rooster gives us an extra 2 legs. A difference of 8 legs will provide 4 pigs, the other 7 roosters.
An interesting project. And probably super profitable for the organisers. It is interesting to take a closer look and see if there are any profitable strategies.
11 roosters give us 22 legs, replacing a pig with a rooster gives us an extra 2 legs. A difference of 8 legs will provide 4 pigs, the other 7 roosters.
Divide the number of legs in half, we get 15 pairs of legs, anyhow there are more roosters, so there are at least 7, by trying it out starting with 7 roosters and 4 pigs we find that there were 4 pigs and 7 roosters ))
Mathemat: Well if there were, say, 5000 legs and 1700 tails, it would be a bit difficult to overshoot...
So he counted legs dashingly )))), and also managed to go over tails, he used weak points in problem solving at school. Well, that's just for the answer.
11 roosters give us 22 legs, replacing a pig with a rooster gives us an extra 2 legs. A difference of 8 legs will provide 4 pigs, the other 7 roosters.
http://winnland.net/auction.php?aid=412
An interesting project. And probably super profitable for the organisers. It is interesting to take a closer look and see if there are any profitable strategies.
11 roosters give us 22 legs, replacing a pig with a rooster gives us an extra 2 legs. A difference of 8 legs will provide 4 pigs, the other 7 roosters.
Well if there were, say, 5000 legs and 1700 tails, it would be a bit difficult to overshoot...
There is a known case - a Hindu, I think - where a man could instantly count about this number of objects without making any mistakes.