Pure maths, physics, logic (braingames.ru): non-trade-related brain games - page 86
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!!
thistwenty!!!!!!
Everyone watch)))
If we have applied K(m+delta)g to a small one, only K*delta*g acts on the spring, as Kmg goes to friction. Is this wrong?
I don't understand how you can move a body of mass (M+m) by applying less than K(M+m)g.
So you move one crate first, and when it stops, the second moves. No paradox)))
Yeah. So the force required is divided by the number of crates.
// But where does the "necessary distance" always dissipate? There is no way without it, it is already sorted out!
// But where does the "necessary distance" go all the time? It's impossible without it, it's been clarified!
P.S. I have the impression that this is also a forum virus like the plane problem.
Don't troll me))
Seriously, it's not the "required distance" that really matters, but the "required time" (from acceleration to recoil), and this depends on the spring stiffness.
// Well, the "necessary distance" depends on that too, of course. :)
It is clear that the force needed is less than K(m+M)g. By a positive delta. It is clear that the delta depends on how much distance (and therefore time) the baby has to spare before the spring will bounce it back. I.e. the spring stiffness is not only important, it is also the main thing in all this jostling.
Waiting for Alsou from the handbook.
It is all logical, but it is also logical that the stored kinetic energy will depend on the time elapsed from the start of the first body's movement until the second body shifts (because the force is constant). Therefore: the softer the spring, the less force is needed.
It doesn't seem to stall, for this reason: if we were able to displace the centre of mass of the system once by the force F, we can do it any number of times more.
Everyone watch))
Downloaded for myself.
// Unfortunately I can understand bourgeois at this pace through a sentence, even in the text version. (No way to listen to it.)
// I'll pause and rewatch at my leisure. Interesting.