MathRand()
MathRand function returns a pseudorandom integer in the range 0 to 0x7fff (32767)
bool buy = MathRand()/32768.0 >= 0.5, sell= !buy;
I don't understand how to proceed.
If I write
int random = MathRand() ; double check = random/32768 ; Print( check ) ;
I obtain 0.
Alberto_jazz:
I don't understand how to proceed.
If I write
I obtain 0.
Don't divide an int by an int and expect a double . . . read up on type casting
Try . . .
int random = MathRand() ; double check = random/32768.0 ; //<---- 32768.0 Print( check ) ;
Why not just use:
int random = MathRand() ; if(random % 2 ==0){Buy();}else{Sell();}
//define a variable e.g x
{
int x;
m_Symbol.RefreshRates();
x=MathRand();
Print("x = ",x,", Bid = ",m_Symbol.Bid(),", Ask = ",m_Symbol.Ask());
if(x<16384) //this your choice --buy
{
if(m_Trade.PositionOpen(Symbol(),ORDER_TYPE_BUY,GetSize(),m_Symbol.Ask(),
m_Symbol.Bid() - (Points * StopLoss),
m_Symbol.Ask()+(Points*ProfitTarget)))
{
OrderNumber=m_Trade.ResultOrder();
return(true);
}
else
{
OrderNumber=0;
}
}
else //------sell short
{
if(m_Trade.PositionOpen(Symbol(),ORDER_TYPE_SELL,GetSize(),m_Symbol.Bid(),
m_Symbol.Ask() + (Points * StopLoss),
m_Symbol.Bid() -(Points * ProfitTarget)))
{
OrderNumber=m_Trade.ResultOrder();
}
else
{
OrderNumber=0;
}
}
return(false);
}
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Hi all, could you give a criteria on how to use MathRand() function to open orders?
Something like this:
if ( MathRand() ....)
BUY
if ( MathRand() ...)
SELL
Betterif these two conditions have around 50% probability each one.
For istance, if MathRand() is an equal number BUY, else SELL.
Hope is clear!
Thank you!