Active 9 Hours

[Dua Yong Rew]

Hi all,

Any ideas to go about finding which 9 hours range got the highest high and the lowest low of the day for consecutive x number of days

example
i need to find the 9 hour range of the day with the max high and min low and collect and compare over a few days data for a normalize value
like period between 4am - 1pm...

[rv]

doshur wrote >>
Hi all,

Any ideas to go about finding which 9 hours range got the highest high and the lowest low of the day for consecutive x number of days

High[iHighest....)]
Low[iLowest..)]
is the idea. the definition you find here https://docs.mql4.com/series

[Dua Yong Rew]

but how do i get the most active 9 hours range of which have the highest and lowest?

[William Roeder]

double range.max=0;
for (int shift=9; shift >=0; shift--) {
   double range=High[shift]-low[shift];
   if (range>range.max) int shift.tallest=shift;
}

[Dua Yong Rew]

WHRoeder wrote >>

  how can i do this to find the best performing 9 hours range for maybe the consecutive 10 days?
I need to get a normalize value

[rv]

doshur wrote >>

how can i do this to find the best performing 9 hours range for maybe the consecutive 10 days?
I need to get a normalize value

High[iHighest....)]
Low[iLowest..)]

Loop over 9 days (9 days*24 hours) and rember the best performing range ...