关于调用指标数组内值得问题

Fa Cao 2013.12.03 06:19

做了一个指标 Indicator_1，然后在EA中调用，打印指标数组中的数据，结果有些乱，详情如下：

Indicator_1代码：

#property indicator_chart_window
#property indicator_buffers 1
#property indicator_color1 Yellow 
double Bar_High[]; 

int init()
  {
  IndicatorShortName("High_Low_Two_Lines");
  IndicatorBuffers(1);
  SetIndexBuffer(0,Bar_High);
  SetIndexStyle(0,DRAW_LINE);
  SetIndexLabel(0,"High Point Line");
  SetIndexDrawBegin(0,0);
  return(0);
  }

int deinit()
  {
   return(0);
  }

int start()
  {
    int counted_bars=IndicatorCounted();
    if(counted_bars>0)int limit=Bars-counted_bars-1;
    limit=Bars-counted_bars;
    for(int i=0;i<limit;i++)
    {
    Bar_High[0]=High[iHighest(NULL,0,MODE_HIGH,10,0)];
    Print("Bar_High[0-9]:",Bar_High[0]," , ",Bar_High[1]," , ",Bar_High[2]," , ",Bar_High[3]," , ",Bar_High[4]," , ",Bar_High[5]," , ",Bar_High[6]," , ",Bar_High[7]," , ",Bar_High[8]," , ",Bar_High[9]);
    }
   return(0);
  }

EA代码为：


int init()
  {
   return(0);
  }
int deinit()
  {
   return(0);
  }

int start()
{
   iCustom(NULL,0,"High_Low_Ind",30,40,50,0,0);
  return(0);
}

用历史数据测试结果为：这个结果有问题，指标缓存Bar_High[0]每获取一个值，则原来的值应该赋给Bar_High[1], Bar_High[1]原来值给Bar_High[2],以此类推，但是结果并非如此，请问是哪里出问题了？

2013.12.03 15:11:49 2013.11.28 23:59 High_Low_Ind USDJPY,M15: Bar_High[0-9]:102.347, 102.287, 102.286, 102.268, 102.257, 102.257, 102.294, 102.294, 102.294, 102.294

2013.12.03 15:11:49 2013.11.28 23:58 High_Low_Ind USDJPY,M15: Bar_High[0-9]:102.347, 102.287, 102.286, 102.268, 102.257, 102.257, 102.294, 102.294, 102.294, 102.294

...........

2013.12.03 15:11:49 2013.11.28 23:54 High_Low_Ind USDJPY,M15: Bar_High[0-9]:102.325, 102.287, 102.286, 102.268, 102.257, 102.257, 102.294, 102.294, 102.294, 102.294

2013.12.03 15:11:49 2013.11.28 23:53 High_Low_Ind USDJPY,M15: Bar_High[0-9]:102.325, 102.287, 102.286, 102.268, 102.257, 102.257, 102.294, 102.294, 102.294, 102.294

2013.12.03 15:11:49 2013.11.28 23:53 High_Low_Ind USDJPY,M15: Bar_High[0-9]:102.322, 102.287, 102.286, 102.268, 102.257, 102.257, 102.294, 102.294, 102.294, 102.294

2013.12.03 15:11:49 2013.11.28 23:53 High_Low_Ind USDJPY,M15: Bar_High[0-9]:102.32, 102.287, 102.286, 102.268, 102.257, 102.257, 102.294, 102.294, 102.294, 102.294

2013.12.03 15:11:49 2013.11.28 23:53 High_Low_Ind USDJPY,M15: Bar_High[0-9]:102.318, 102.287, 102.286, 102.268, 102.257, 102.257, 102.294, 102.294, 102.294, 102.294

okwh 2013.12.03 12:37 #1

Bar_High[0]=High[iHighest(NULL,0,MODE_HIGH,10,0)];

你只给下标0的元素赋值，还能得到那么多？因为mt不是那样类推的，如果是那样推，用i有什么意义？

应该改为：

Bar_High[i]=High[iHighest(NULL,0,MODE_HIGH,10,i)];

Fa Cao 2013.12.03 22:54 #2

DxdCn:

Bar_High[0]=High[iHighest(NULL,0,MODE_HIGH,10,0)];

你只给下标0的元素赋值，还能得到那么多？因为mt不是那样类推的，如果是那样推，用i有什么意义？

应该改为：

Bar_High[i]=High[iHighest(NULL,0,MODE_HIGH,10,i)];

谢谢回复，有道理，还有一个问题想请教一下：

比如此例，指标缓存数组为Bar_High[]，如果代码如下写：

Bar_Shift=iHighest(NULL,0,MODE_HIGH,10,i);

Bar_High[i+Bar_Shift]=High[Bar_Shift];

即是想实现这样的功能：从当前Bar开始，往前推10根Bar，选出其中最高的一根，然后将选出的所有的”最高的“Bar作为指标连接成线；请问这样用指标实现是否合适？

okwh 2013.12.04 03:39 #3

可以，当然你知道这是事后画点和线，有延迟，是类似ZigZag和fractal的指标。

Bar_Shift是i到i+10之间的值，不是0~10之间的值，不需要加i，所以

Bar_High[Bar_Shift]=High[Bar_Shift]; 即可

参考弄清i 是什么，如何随时间变化

https://book.mql4.com/samples/icustom

Fa Cao 2013.12.04 05:56 #4

谢谢！

BaiChun Li 2013.12.06 03:43 #5