I would compute a variable datetime and a type int, like 2009.01.06 + 3 (this is easy in Excel). Can you help me, how to procede the good script ?
I would compute a variable datetime and a type int, like 2009.01.0e 6 + 3 (this is easy in Excel). Can you help me, how to procede the good script ?
1. Correct me if I'm wrong, that is 3 days after Jan 6th, 2009, right ? Not 3 hours, or 3 months .
2. Datetime type is actually an integer. Here's what the doc says (https://www.mql5.com/en/docs/basis/types/integer/datetime) , that datetime is "intended for storing the date and time as the number of seconds elapsed since January 01, 1970" .Read the one that I highlighted.
That mean to add just one day to a datetime is the same with adding 86400 to a datetime. That's because the number of second that elapsed in a day is equal with 86400 seconds (= 24 hours * 60 minutes * 60 seconds).
Just make sure you write the datetime format correctly.
datetime today = 0;
int a_day = 86400;
a_day = today + a_day;
Alert (TimeToString (a_day, TIME_DATE| TIME_SECONDS));