Understanding CopyBuffer memory allocation

[pbMoney]

I am using the following EMA set up.

emaFastCloseHandle = iMA(_Symbol, _Period, emaFastPeriod, 0, MODE_EMA, PRICE_CLOSE);
emaSlowCloseHandle = iMA(_Symbol, _Period, emaSlowPeriod, 0, MODE_EMA, PRICE_CLOSE);

My initial thoughts were doing the following

double fastEma[2];

CopyBuffer(emaFastCloseHandle, 0, 0, 2, fastEma);

would mean

double ema = fastEma[0];  // latest value
double ema1 = fastEma[1]; // previous value

After testing this and seeing some unexpected behaviour and then reading this https://www.mql5.com/en/docs/series/copybuffer, I am thinking my initial were incorrect and in fact it is

double ema = fastEma[
1 ];  // latest value
double ema1 = fastEma[
0 ]; // previous value

Can someone please confirm this to make sure I am not going mad!?!?

Also, I have written the following two functions and wanted someone to just clarify that the following conditions are correct for the function names? 

bool isFastEmaCrossingUnderSlow() {
   double fastEma[2], slowEma[2];

   if (CopyBuffer(emaFastCloseHandle, 0, 1, 2, fastEma) <= 0) return false;
   if (CopyBuffer(emaSlowCloseHandle, 0, 1, 2, slowEma) <= 0) return false;

   return (fastEma[1] < slowEma[1]) && (fastEma[0] > slowEma[0]);
}

bool isFastEmaCrossingOverSlow() {
   double fastEma[2], slowEma[2];

   if (CopyBuffer(emaFastCloseHandle, 0, 1, 2, fastEma) <= 0) return false;
   if (CopyBuffer(emaSlowCloseHandle, 0, 1, 2, slowEma) <= 0) return false;

   return (fastEma[1] > slowEma[1]) && (fastEma[0] < slowEma[0]);
}

[Alain Verleyen]

pbMoney:

I am using the following EMA set up.

My initial thoughts were doing the following

would mean

After testing this and seeing some unexpected behaviour and then reading this https://www.mql5.com/en/docs/series/copybuffer, I am thinking my initial were incorrect and in fact it is

Can someone please confirm this to make sure I am not going mad!?!?

Yes, exact. 

Also, I have written the following two functions and wanted someone to just clarify that the following conditions are correct for the function names? 

Yes correct. Though you should manage the '=' condition, it happens !