// Define the function to get the ticket ID of the most negative position ulong GetMostNegativePositionTicket() { ulong mostNegativeTicket = 0; double mostNegativeProfit = 0; // Loop through all open positions for (int i = 0; i < PositionsTotal(); i++) { // Get the position by index if (PositionSelectByIndex(i)) { // Check if the position's profit is less than the current most negative profit if (PositionGetDouble(POSITION_PROFIT) < mostNegativeProfit) { mostNegativeProfit = PositionGetDouble(POSITION_PROFIT); mostNegativeTicket = PositionGetInteger(POSITION_TICKET); } } } return mostNegativeTicket; } // Example usage void OnStart() { ulong mostNegativeTicket = GetMostNegativePositionTicket(); Print("Most negative position ticket ID: ", mostNegativeTicket); }

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Hello there!
Is there a way to get the ticket ID of the most negative position?
Theoretically this would be the first opened position in grid system. I thought storing all position tickets in an array would do but this seems like a mountain of a task. So i thought looping through all open positions would be the path of least resistance but it seems the shortcut is actually the longer way.
Any advice is much appreciated thanks!