The problem of free falling body is not a free-falling body; There isn’t one, or there won't be - General

TheXpert 2017.03.28 21:14 #71

Алексей Тарабанов:
Which one is yours, I wonder?

There isn't one.

TheXpert 2017.03.28 21:15 #72

Алексей Тарабанов:
Which one is yours, I wonder?

There isn't one.

Алексей Тарабанов 2017.03.28 21:23 #73

Комбинатор:
There is no such thing.

Not yet, or there isn't and won't be?

Dmitry Fedoseev 2017.03.28 21:33 #74

Комбинатор:

sqrt(2gh), not serious.

...

This is not a free-falling body. The driving force is tangentially directed. At the initial point of motion, the body has a force of 0. Only at the end of the trajectory does the full force of gravity act on the body. The force applied to the body varies with the angle. We have to make a diphour and solve it. I don't know what the final result will be, but don't be in a hurry for an answer.

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Алексей Тарабанов 2017.03.28 21:45 #75

I'm worried about where everyone has gone. We should talk more often...

Yuriy Asaulenko 2017.03.28 22:07 #76

Dmitry Fedoseev:
This is not a free-falling body. The driving force is tangentially directed. At the starting point of the movement, the body is subjected to a force of 0. Only at the end of the trajectory does the full force of gravity act on the body. The force applied to the body varies with the angle. We have to make a diphour and solve it. I don't know what the final result will be, but don't be in a hurry for an answer.

We don't need a diffraction. If we dance from the initial energy and linearity of the velocity from the column height. An integral like mgH/2=integral(m/H *v(h)^2/2*dh). It goes something like this. Since the velocity is linear with the height, it is not difficult to solve. And v(h)=kh.

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Dmitry Fedoseev 2017.03.28 22:53 #77

Isn't m/H *v(h)^2/2*dh a difur? All in all, your knowledge of termechanics is not impressive. Sorry about that.

Yuriy Asaulenko 2017.03.28 22:58 #78

Dmitry Fedoseev:
Isn't m/H *v(h)^2/2*dh a difur? All in all, your knowledge of termechanics is not impressive. Sorry about that.

I wasn't trying to impress you.) I understand you can't do that either.)

Dmitry Fedoseev 2017.03.28 22:59 #79

And another thing... True adepts of termechanics even when solving the problem of a free falling body make up a difur. There is no such thing as a term theory without difurbs.

Dmitry Fedoseev 2017.03.28 23:01 #80

Yuriy Asaulenko:
I wasn't trying to impress you.)

Yes? But still, someone is very impressive:

Yuriy Asaulenko:
Well, it's nothing. Centre of mass in the middle. Energy is mgh/2. moving on arc of circle. But I am too lazy to calculate).

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