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the condition is not met, how to break

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Thank you very much I can use it as it is now.

Will you pls confirm next step and send source code then we finish the job.

Esse:
Kicking it hard...
Minions Labs:
Kicking it hard...

And if that doesn't work, kick it again.

Look here: https://docs.mql4.com/basis/operators/if

Anthony Garot:

And if that doesn't work, kick it again.

Look here: https://docs.mql4.com/basis/operators/if

Thank you for link.

it was like that:

for(x=0; x<201; x++){
if(
Open(5+x) < Close (5+x) &&
Open(4+x) < Close (4+x) &&
Open(3+x) < Close (3+x) &&
Open(2+x) < Close (2+x) )
}

I changed to:

for(x=0; x<201; x++){

if (Open(5+x) < Close (5+x)) continue; else break; 
if (Open(4+x) < Close (4+x)) continue; else break; 
if (Open(3+x) < Close (3+x)) continue; else break; 
if (Open(2+x) < Close (2+x)) continue; else break; 
}
nr_line=x

It's ok now?

Esse:

It's ok now?

Not exactly sure what you are trying to do here, but you could simplify your code by doing the following:

for(x=0; x<201; x++)
{
    if (Open(5+x) >= Close(5+x)) break; 
    if (Open(4+x) >= Close(4+x)) break; 
    if (Open(3+x) >= Close(3+x)) break; 
    if (Open(2+x) >= Close(2+x)) break; 
}
Anthony Garot:

Not exactly sure what you are trying to do here, but you could simplify your code by doing the following:

Thanks, it's works!!


The code has accelerated - 17 times faster:

8 minut 25 sekund ===> now: 30 sekund

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