e.g. for a= 211.2 => 210 (=b):
double b = 10.0*(double)((int)(a/10.0))
Guilherme Mendonca: I would like to know, how to round a number and keep the last digit only 0 or 5.
/** Round a double to a multiple of an amount. * @param[in] v Value to round. * @param[in] to The multiple. */ double round_down( double v, double to){ return to * MathFloor(v / to); } /// Round a double to a multiple of an amount. double round_up( double v, double to){ return to * MathCeil( v / to); } /// Round a double to a multiple of an amount. double round_nearest( double v, double to){ return to * MathRound(v / to); } //////////////////////////////////////////////////////////////////////////////// round_nearest(104.5, 5) // 105.0 round_nearest(102, 5) // 100.0 round_nearest(211.2, 5) // 210.0 round_nearest(1.23452, 5*_Point) // 1.23450 round_nearest(1.23456, 5*_Point) // 1.23455 (_Point=0.00001) round_nearest(1.23458, 5*_Point) // 1.23460
whroeder1:
whroeder1:
Thank you!
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I would like to know, how to round a number and keep the last digit only 0 or 5.
For example:
Round (104,5) = 105
Round (102) = 100
Round (211,2) = 210