hakona: could any one tell me please the logic behind that pattern , how to program it ,,, just the idea not the code
The hard part is splitting the chart into the 3 parts (a, b, and c)Not compiled, not tested.
int iHi = LocalExtremeBar(LE_Window, 0, +1), iLo = LocalExtremeBar(LE_Window, 0, -1); if(iHi > iLo){ // As pictured int iC = iHi; int iB = LocalExtremeBar(LE_Window, iC, -1); // End of A/Start of B int iA = LocalExtremeBar(LE_Window, iB, -1); // Start of A if(High[iA] > High[iC] && Low[0] > (High[iB] + Low[iB])/2.0 ){ // Pattern confirmed :Not compiled, not tested.
Pre Build 600
int LocalExtremeBar(int length, int start, double d){ if (d > 0.0) return LocalExtremeArray(High, length, start, d); return LocalExtremeArray( Low, length, start, d); } int LocalExtremeArray(double arr[], int length, int iStart, double d){ while(true){ int iPrev = iStart; iStart = ArrayExtrema(arr, length, iStart, d); if (iStart == iPrev) break; } return(iStart); } int ArrayExtrema(double arr[], int length, int iStart, double d){ // Like ArrayMaximum but with direction and duplicate control. int iExtreme = iStart; double value = arr[iExtreme]; int iLimit = MathMin(iStart + length, ArraySize(arr)); for(iStart++; iStart<iLimit; iStart++) if( (arr[iStart]-value) *d >= 0.){ iExtreme = iStart; value = arr[iExtreme]; } // largest index (>=) return iExtreme; }Pre Build 600
thank u
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could any one tell me please the logic behind that pattern , how to program it ,,, just the idea not the code