StringFormat(":%06.3f",v) = "00v.123" how?

[Carl Schreiber]

Hi,

I tried various version to get what is not problem with int-values - leadiing zeros if a value is to small: 11 => "011"?

I have the double v = 5.123 I want to get the string "005.123" using StringFormat("",v);

Anybody knows how?

Thanks in advance,

Gooly

[Syed Naufal Gaddafi]

The usual trick is to use string with 00 inside and combines it with respective int whenever the int is below 10.

[honest_knave]

gooly:

Hi,

I tried various version to get what is not problem with int-values - leadiing zeros if a value is to small: 11 => "011"?

I have the double v = 5.123 I want to get the string "005.123" using StringFormat("",v);

Anybody knows how?

Thanks in advance,

Gooly

   double v = 5.123;
   string Test = StringFormat("%07.3f",v);
   Print(Test);

You were 1 digit short. Should be 7 (remember the decimal point counts)

[Alain Verleyen]

gooly:

Hi,

I tried various version to get what is not problem with int-values - leadiing zeros if a value is to small: 11 => "011"?

I have the double v = 5.123 I want to get the string "005.123" using StringFormat("",v);

Anybody knows how?

Thanks in advance,

Gooly

   double var=5.123;
   Print(StringFormat("%07.3f",var));

[Carl Schreiber]

honest_knave:

You were 1 digit short. Should be 7 (remember the decimal point counts)

Ah - ok! Thank you, angevoyageur too.

As I read it I remember!