How much is the "grail" worth? - page 10
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Alexei, that phrase is from the dimeon website
I drew from :)
By the way, what does it mean: "little money"?
Tu hum hau, as they say among MGIMO graduates :)
Pardon - DipAcademy :)
"Medium risk" - given that the costs are minimal. The risk of 700 quid on a deposit of 1000 is still not much, as it is small money. However, the risk of 7000 on a 10,000 deposit is already a disaster.
Hot Estonian boys, what are you talking about? Bears wake up, it's going to be bad!
This is indeed a non-trivial problem:
The trading results of the system with n trades are given. The maximum drawdown is dd %. What is the probability that with additional N trades the maximum drawdown in the new area will not exceed DD %?
The sequence of trades of the system is a Bernoulli scheme with known probability of success p and known ratio of average profitable trade to average losing trade alpha.
This is indeed a non-trivial problem:
The trading results of the system with n trades are given. The maximum drawdown is dd %. What is the probability that with additional N trades the maximum drawdown in the new area will not exceed DD %?
The sequence of trades of the system is a Bernoulli scheme with known probability of success p and known ratio of average profitable trade to average losing trade alpha.
There you go again about probability ...
Are we "on a first-name basis"?
The problem has been bothering me for a long time, because I often see here an experienced bisonman instructing a neophyte who has posted a straight: "Multiply the maximal drawdown by half, or better by three times".
This is indeed a non-trivial problem:
The trading results of the system with n trades are given. The maximum drawdown is dd %. What is the probability that with additional N trades the maximum drawdown in the new area will not exceed DD %?
The sequence of trades of the system is a Bernoulli scheme with known probability of success p and known ratio of average profitable trade to average losing trade alpha.