Return Positive value of a number

[Guilherme Mendonca]

Is there a diferent way or a function to return the positive value of a number?

I know I can use this kind of code, but is there any simple way?

if(number<0)
     number=number*-1;

[Amine Abed]

MathAbs

[Guilherme Mendonca]

Amine Abed #:
MathAbs

Thanks!

[Dominik Egert]

Here are manual versions:

number=number*(-1 + (2 * (number > -1)));
number=(number < NULL) ? number * -1 : number;

[Alain Verleyen]

Dominik Egert #:

Here are manual versions:

You really like to complicate things :-D

[Dominik Egert]

Oh, here, try this, it's easier....

😂

#define inline_MathAbs(x) ((x < NULL) ? x * -1: x)
number=inline_MathAbs(number);

[Dominik Egert]

I would dare to claim this version is the fastest possible:

What do you think?

number=number * ((number < NULL) ? -1 : 1)

[Ernst Van Der Merwe]

   number=number<0?-number:number;

[Haruto Rat]

number=sqrt(pow(number,2));

For those who _really_ like to complicate things and spend resources. :)

[Amir Yacoby]

There can be a bit negation as well

pos=~num+1

but the fastest way should be

MathAbs

if the compiler is written correctly, because the function should develop to the fastest machine code available

[Guilherme Mendonca]

Thanks folks.

It’s very useful this kind of post with many suggestions. 

I think the best users choice should be the fastest way.