A problem of Ema cross?

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hello everybody,

i have a problem with Ema of Cross in the mql4.
i want to konw how could i realize when the two Ema lines had crossd then appear a sylbol in the chart like following picture.






thanks a lot
 
hello everybody,

i have a problem with Ema of Cross in the mql4.
i want to konw how could i realize when the two Ema lines had crossd then appear a sylbol in the chart like following picture.

thanks a lot

In essence you must find state of (b-y) at a bar and state of (b-y) at bar+1 to be oposite.
b[]=Blue
y[]=Yellow
i = bar

FirstCrossing=0;
SecondCrossing=0;
if ((b[i+1]-y[i+1]) <=0 && (b[i]-y[i])>0)  FirstCrossing=1;
i--; to second crossing
if ((b[i+1]-y[i+1]) >=0 && (b[i]-y[i])<0)  SecondCrossing=1;
,
,
,
,




bbbbbbbyyyyyyyyy
yyyyyyyybbbbbbbb
............^
Ideal cross


Please Notice "=0" it may be placed at i+1 or i or both depends on your need. However, cross point may take several bars.
bbbbbbb00000yyyyyy
yyyyyyyy00000bbbbbb
............^
....................^
Possible crosses detected.

This will be considered as cross too
bbbbbbb00000bbbbbbb
yyyyyyyy00000yyyyyyyy

The actual code will depend on what you want.


 
Create a custom indicator with two ExtMapBuffers.
Set the buffers to type arrow (SetIndicatorStyle, SetIndicatorArrow).

Then: 

ema1= iMa(......, shift);
ema2= iMa(......, shift);
ema1x= iMa(......, shift+2);
ema2x= iMa(..... , shift+2),

diffnow= ema1 - ema2;
diffprev= ema1x - ema2x;

if (diffnow>0 && difprev<0) {
   ExtMapBufLong[shift+1]= Low[shift+1];
}


if (diffnow<0 && difprev>0) {
   ExtMapBufShort[shift+1]= High[shift+1];
}



Not perfect but a good approximation.



Markus

 
hello everybody,

i have a problem with Ema of Cross in the mql4.
i want to konw how could i realize when the two Ema lines had crossd then appear a sylbol in the chart like following picture.

thanks a lot

In essence you must find state of (b-y) at a bar and state of (b-y) at bar+1 to be oposite.
b[]=Blue
y[]=Yellow
i = bar

FirstCrossing=0;
SecondCrossing=0;
if ((b[i+1]-y[i+1]) <=0 && (b[i]-y[i])>0)  FirstCrossing=1;
i--; to second crossing
if ((b[i+1]-y[i+1]) >=0 && (b[i]-y[i])<0)  SecondCrossing=1;
,
,
,
,




bbbbbbbyyyyyyyyy
yyyyyyyybbbbbbbb
............^
Ideal cross


Please Notice "=0" it may be placed at i+1 or i or both depends on your need. However, cross point may take several bars.
bbbbbbb00000yyyyyy
yyyyyyyy00000bbbbbb
............^
....................^
Possible crosses detected.

This will be considered as cross too
bbbbbbb00000bbbbbbb
yyyyyyyy00000yyyyyyyy

The actual code will depend on what you want.






thank u for your answer

i think the "cross" same with to you.
I)bbbbbbbyyyyyyyyy
yyyyyyyybbbbbbbb
............^
corss

II)bbbbbbb00000yyyyyy
yyyyyyyy00000bbbbbb
....................^
cross


III)bbbbbbb00000bbbbbbb
yyyyyyyy00000yyyyyyyy
................................
not cross
 

Create a custom indicator with two ExtMapBuffers.
Set the buffers to type arrow (SetIndicatorStyle, SetIndicatorArrow).

Then: 

ema1= iMa(......, shift);
ema2= iMa(......, shift);
ema1x= iMa(......, shift+2);
ema2x= iMa(..... , shift+2),

diffnow= ema1 - ema2;
diffprev= ema1x - ema2x;

if (diffnow>0 && difprev<0) {
   ExtMapBufLong[shift+1]= Low[shift+1];
}


if (diffnow<0 && difprev>0) {
   ExtMapBufShort[shift+1]= High[shift+1];
}



Not perfect but a good approximation.



Markus



thanks,i try it.
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